A leaky parallel plate capacitor is filled completely with a material having dielectric constant K = 5 and electric conductivity σ = 7.4 × 10 –12 Ω –1 m –1 . If the charge on the plate at the instant t = 0 is q = 8.85 µC, then the leakage current at the instant t = 12 sec is………× 10 –1 µA.
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(2)
Sol. As in case of discharging of a capacitor through a resistance
q = q 0 
i = – 
Here, CR = 
[as ρ = 1/σ]
i.e., CR = 
= 6
So, i = 
= 
[As e = 2.718, e 2 = 7.39]
= 0.20 µ A
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